Lesson Topics Discussion Quiz: Class Homework |
Steps-1 |
Title: System of Linear Equations with no Solutions |
Grade Lesson s5-l8 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
Id | Type | Name | Note |
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1 |
Problem |
If there is no solution of the linear equation system 4x + 5y = 5, 2x + ky = 9, then find the value of k? |
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2 |
Step |
Consider the two linear equations are |
\$ a_1x + b_1x = c_1 \$…….equation (1) \$ a_2x + b_2x = c_2 \$…….equation (2) |
3 |
Hint |
If equation(1) and equation (2) have no solution then we can write: \$ (a_1)/(a_2) = (b_1)/(b_2) ne (c_1)/(c_2) \$ …….equation (3). |
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4 |
Step |
First, we will compare 4x + 5y = 5 with equation (1) and 2x + ky = 9 with equation (2). So by comparing the coefficients, we can write: |
\$a_1 = 4, a_2 = 2, b_1 = 5, b_2 = k, c_1 = 5, c_2 = 9\$ |
5 |
Step |
Now substitute the values in equation (3) then simplify: |
\$ 4/2 = 5/k ne 5/9 \$ …….equation(3) \$ 4/2 = 5/k \$ \$ 4k = 10 \$ |
6 |
Step |
Solve for k value: |
\$ (\cancel(4^1)k)/(\cancel4^1) = (\cancel10^5)/(\cancel4^2) \$ \$ k = 5/2 \$ |
7 |
Solution |
Therefore, the value of k is \$ 5/2\$. |
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8 |
Sumup |
Please summarize steps |
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Choices |
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9 |
Choice-A |
This option is wrong: It represents the inverse of the correct value for k |
Wrong \$ k = 2/5\$ |
10 |
Choice-B |
This option is wrong: It represents the negative value but the k is the positive value |
Wrong \$ k = -5/2\$ |
11 |
Choice-C |
This option is wrong: It represents the inverse of the correct value for k and sign is negative |
Wrong \$ k = -2/5\$ |
12 |
Choice-D |
This option is correct: It represents the correct value by using the formula |
Correct \$ k = 5/2\$ |
13 |
Answer |
Option |
D |
14 |
Sumup |
Please summarize choices |
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