Lesson Topics Discussion Quiz: Class Homework |
Steps-4 |
Title: Non-linear equations in one variable |
Grade Lesson s5-l6 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
Id | Type | Name | Note |
---|---|---|---|
1 |
Problem |
Solve the non-linear equation \$x^3 - 5x^2 + 6x = 0\$. |
|
2 |
Step |
The given non-linear equation |
\$x^3 - 5x^2 + 6x = 0\$ |
3 |
Step |
Rewrite the equation into quadratic form: |
\$x(x^2 - 5x + 6) = 0\$ x = 0 and \$x^2 - 5x + 6 = 0\$ |
4 |
Formula |
The quadratic formulae is \$ x = (- b ± \sqrt(b^2 - 4ac)) / (2a) \$. |
|
5 |
Step |
Plug in the corresponding values using the quadratic formulae: |
Where a = 1, b = - 5, and c = 6 \$x = (-(- 5) ± \sqrt((-5)^2 - 4(1)(6))) / (2(1))\$ \$x = (5 ± \sqrt(1)) / 2\$ |
6 |
Step |
The two possible answers are: |
\$x = (5 + 1) / 2 \$ or \$x = (5 - 1) / 2\$ x = 3 or x = 2 |
7 |
Solution |
Therefore, the solutions to the equation is \$x^3 - 5x^2 + 6x = 0 are x = 0, x = 2, and x = 3\$. |
|
8 |
Sumup |
Please summarize steps |
|
Choices |
|||
9 |
Choice-A |
x = - 2 and x = - 3, does not satisfy the equation when substituted back into \$x^3 - 5x^2 + 6x = 0\$, so it is not correct |
Wrong x = - 2 and x = - 3 |
10 |
Choice-B |
It is not correct because it provides the values x = 2 and x = 3, but it misses the solution x = 0 |
Wrong x = 2 and x = 3 |
11 |
Choice-C |
Option C, x = 1 and x = - 2, is incorrect because x = 1 is not a solution to the equation |
Wrong x = 1 and x = - 2 |
12 |
Choice-D |
This is correct as it includes all the accurate roots of the provided equation |
Correct x = 0, x = 2, and x = 3 |
13 |
Answer |
Option |
D |
14 |
Sumup |
Please summarize choices |
Copyright © 2020-2024 saibook.us Contact: info@saibook.org Version: 4.0 Built: 13-Mar-2025 12:00PM EST