Lesson Topics Discussion Quiz: Class Homework |
Steps-1 |
Title: Algebra |
Grade Lesson s5-p2 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
Id | Type | Name | Note |
---|---|---|---|
1 |
Problem |
Simplify the expression \$((2x^3y^2)(-3xy^4)^2)/(6x^4y^3)^2\$. |
|
2 |
Step |
Given expression is |
\$((2x^3 y^2)(-3xy^4)^2)/(6x^4 y^3)^2\$ |
3 |
Step |
First, let’s simplify each part individually: |
\$(2x^3 y^2) = 2x^3 y^2\$ \$(- 3xy^4)^2 = (-3)^2 \times (x)^2 \times (y^4)^2 = 9x^2y^8\$ \$(6x^4 y^3)^2 = 6^2 \times (x^4)^2 \times (y^3)^2 = 36x^8 y^6\$ |
4 |
Step |
Now plug these values back into the expression: |
\$((2x^3 y^2)(9x^2 y^8))/(36x^8 y^6)\$ |
5 |
Step |
Combine like terms by multiplying coefficients and adding exponents of variables: |
\$(2 \times 9 \times x^3 \times x^2 \times y^2 \times y^8)/(36 \times x^8 \times y^6)\$ \$(18x^5 y^10)/(36x^8 y^6)\$ \$(x^5 y^10)/(2x^8 y^6)\$ |
6 |
Step |
After simplification: |
\$(1/2) \times (x^5) / (x^8) \times (y^10) / (y^6)\$ \$(1/2) \times x^(5 - 8) \times y^(10 - 6)\$ \$(1/2) \times x^(- 3) \times y^4\$ \$(1/2) \times (y^4) / (x^3)\$ |
7 |
Solution |
Therefore, the simplified expression is \$(1/2) \times (y^4) / (x^3)\$. |
|
8 |
Sumup |
Please summarize steps |
|
Choices |
|||
9 |
Choice-A |
Option A inaccurately presents \$−(y^4)/(2x^3)\$, due to the inclusion of a negative sign, rendering it incorrect |
Wrong \$ -(y^4) / (2x^3)\$ |
10 |
Choice-B |
It simplifies to \$y^3/(2x^2)\$, differing from our derived simplified form, thus incorrect |
Wrong \$ (y^3) / (2x^2)\$ |
11 |
Choice-C |
Correct: It precisely performs the calculations with accuracy |
Correct \$ (1/2) \times (y^4) / (x^3)\$ |
12 |
Choice-D |
\$−(y^3)/(2x^2)\$, is invalid as it diverges from the simplified expression due to calculation errors |
Wrong \$ -(y^3) / (2x^2)\$ |
13 |
Answer |
Option |
C |
14 |
Sumup |
Please summarize choices |
Copyright © 2020-2024 saibook.us Contact: info@saibook.org Version: 4.0 Built: 25-June-2025 12:00PM EST