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Example1

Title: Geometry

Grade Lesson s4-p2

Explanation: The best way to understand PSAT-4 is by looking at some examples. Take turns and read each example for easy understanding.

Examples

Topics → Definition Example1 Example2

What’s the area of a 3D shape with a side length of 6 m, a height of 6 m, a radius is 4 m, and a width of 5 m? Use the value π is 3.14.

Step: 1

The first 3D shape is a cube.

First, calculate the area of a cube using the formula: \$A = 6a^2 = 216 m^2\$.

Explanation:

In this step, the initial 3D shape is a cube. First, calculate the area of the cube using the formula: \$A = 6a^2 = 216 m^2\$.

Step: 2

The next 3D shape is cuboid.

To calculate the surface area of a cuboid, use the formula: 2(lw + lh + wh) where 192m sq.m represents the total area.

Explanation:

In this step, calculate the surface area of a cuboid,usinge the formula: 2(lw + lh + wh),

where 'l', 'w', and 'h' represent the length, width, and height, respectively, the total area is 192 sq.m.

Step: 3

The next 3D shape is the cone.

To calculate the surface area of a cone, use the formula: 2πr(h +r) where 251.2 sq.m represents the total area.

Explanation:

In this step, calculate the surface area of a cone, using the formula: 2πr(h + r),

where 'r', and 'h' represent the radius, and height, respectively, then the total area is 215.2 sq.m.