Example1

Title: Multiplication

Grade 4+ Lesson s2-l7

Explanation: The best way to understand multiplication is by looking at some examples. Take turns and read each example for easy understanding.

Examples

TopicsDefinition Example1

Find the product of 59 x 30.

Step: 1

First, place the multiplicand 59 on top and write the multiplier 30 below it.

Next, multiply the ones digit of the multiplier, 0, with the multiplicand 59. This will give you 59 × 0 = 00. Write this as the first partial product on a new line.

1a

.

Explanation:

In this step, we’ll multiply 59 by 0. First, multiply 9 by 0 to get 0. Place 0 in the one’s place. Next, multiply 5 by 0 to get 0. Therefore, the answer is 00, the first partial product placed in one line.

Step: 2

Write a 0 in the one’s column. Multiply 3 by the multiplicand. This will give 59 × 3 = 1770. Finally, we get 1770.

2a

.

Explanation:

In this step, multiply the bottom tens digit, 3, by the number on the top, 9. So, 3 x 9 = 27. Write 7 in the tens place and carry 2 to the next column. For 5 x 3 = 15, add 2 (from the carried-over 2) to get 17, and write 17 next to the 7 you already wrote down. This will give you the final answer of 1770. This is the second partial product placed on another line.

Step: 3

Add both the first and second partial products 00 + 1770=1770.

3a

.

Explanation:

Add both of your results to get a final answer. Now need to add 00 + 1770 to get 1770.

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