Example

Title: Multiplications

Grade: 4-a Lesson: S1-L1

Explanation: The best way to understand multiplications is by looking at some examples. Take turns and read each example for easy understanding.

Examples:

Step: 1a

Find the product of 39 x 17

  • Place the multiplicand 39 on top, and the multiplier is 17.

  • Multiply the ones digit of the multiplier 7 with the multiplicand 39.

  • This will give 39 × 7 = 273. This is the first partial product that will be placed in one line.

1a

.

Explanation: In this step, multiply 39 by 7. Multiply 9 by 7 to get 63. Place 3 in the one’s place, and carry 6 to the tens column. Multiply 3 by 7 to get 21. Add 21 to the carry-over of 6 to get 27. We get the answer is 273. This is the first partial product placed in one line.

Step: 1b

  • Multiplying with the tens column.This will give 39 × 1=39. Write a 0 in the one’s column as shown below .

  • Multiply the one’s digit on the top number with the ten’s digit of the bottom number, i.e., 1 × 9 = 9

  • Multiply the tens digit on the top number and the tens digit of the bottom number, i.e., 1 × 3 = 3. The value of a second partial product is 390.

1b

.

Explanation: In this step, multiply the bottom tens digit, which is 1, by the number on the top which is 9. So, 9 x 1 = 9. Write down the number 9 next to the 0. For 3 x 1 = 3, write down the number 3 next to the 9 that you already wrote down. This way, you will get the final answer of 390. This is the second partial product placed in another line.

Step: 1c

  • Add both partial products to get the final product

  • This will be 273 + 390 =663.

1c

.

Explanation: Add both of your results to get a final answer.
Now need to add 273 + 390 to get 663.


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