Example

Title: Multiplications

Grade: 3-a Lesson: S2-L6

Explanation: The best way to understand multiplications is by looking at some examples. Take turns and read each example for easy understanding.

Examples:

Step: 1a

Multiply 23 by 30.

  • Arrange the numbers 23 and 30 in columns according to their places.

1a

.

Explanation: In this step, arrange the numbers 23 as the multiplicand and 30 as the multiplier.

Step: 1b

  • Multiply 0 by each digit of 23:

  • Start by multiplying 0 by 3, which gives us 0 (0 x 3 = 0). We write 0 in the one’s column.

  • Then, we multiply 0 by 2 (0 x 2 = 0) and write 0 in the tens place.

  • Thus, our final answer is 00.

1b

.

Explanation: In this step, to multiply 0 by each digit of 23, we get 00 as the answer.

Step: 1c

  • Now, we will place a zero (0) under the first partial product, that is, before writing the second partial product in the next line

1c

.

Explanation: In this step, before writing the second partial product in the next line, we will place a zero(0) under the first partial product.

Step: 1d

  • To find the product of 3 multiplied by each digit of 23, follow these steps.

  • Multiplying 3 by 3 gives us 9 (3 x 3 = 9). We write 9 in the ten’s column.

  • Then, we multiply 3 by 2 (3 x 2 = 6) and write 6 in the hundreds column.

  • Our final answer is 690.

1d

.

Explanation: In this step, multiply 3 by each digit of 23. We start with 3. 3 x 3 = 9. Write 9 in the ten’s column. Then, 2 x 3 = 6. Write 6 in the hundreds column. The final answer is 690.

Step: 1e

  • Add both partial products to get the final product

  • This means 00 + 690 = 690.

  • Therefore, the final product is 690.

1e

.

Explanation: Add both results to get a final answer. Now, we need to add 00 + 690 to get 690.


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