Lesson Topics Discussion Quiz: Class Homework |
Steps-2 |
Title: Least common multiple |
Grade 6+ Lesson s1-l3 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
Find the least common multiple: |
|
2 |
Step |
The given data |
41 and 55 |
3 |
Hint |
To find the least common multiple (LCM) of 41 and 55, you can use the prime factorization method. |
|
4 |
Step |
Prime factorization of 41: |
\$ (41)^1 \$ |
5 |
Step |
Prime factorization of 55: |
\$ 5^1 \times (11)^1 \$ |
6 |
Step |
Next, we identify the highest powers of each prime factor. So the highest power of 41 is: |
\$ 41^1 \$ |
7 |
Step |
The highest power of 5 is: |
\$ 5^1 \$ |
8 |
Step |
The highest power of 11 is: |
\$ (11)^1 \$ |
9 |
Step |
Multiply the highest powers of each prime factor together: |
\$ LCM = (41)^1 \times (5)^1 \times (11)^1\$ |
10 |
Step |
Make it simplify: |
\$ "LCM" = 41 \times 5 \times 11 \$ |
11 |
Solution |
So, the least common multiple is 2255. |
|
12 |
Sumup |
Please summarize steps |
|
Choices |
|||
13 |
Choice-A |
2245 cannot be the LCM because it is not divisible by 41 (check \$(2245)/(41) = 54.756\$, not an integer) |
Wrong 2245 |
14 |
Choice-B |
This is incorrect because it isn’t divisible by both 41 and 55 |
Wrong 2265 |
15 |
Choice-C |
2205 cannot be the LCM because it is not divisible by 41 (check \$(2205)/(41) = 53.78\$, not an integer) |
Wrong 2205 |
16 |
Choice-D |
This is the correct answer because it is the least common multiple of 41 and 55 |
Correct 2255 |
17 |
Step |
Option |
D |
18 |
Sumup |
Please summarize choices |
|
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