Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Least common multiple |
Grade: 6-a Lesson: S1-L3 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
Find the least common multiple 23 and 21. |
|
2 |
Hint |
To find the least common multiple (LCM) of 23 and 21, you can use the prime factorization method. |
|
3 |
Step |
Prime factorization of 23: |
\$ 23^1\$ |
4 |
Step |
Prime factorization of 21: |
\$ 3^1*7^1 \$ |
5 |
Step |
Next, we identify the highest powers of each prime factor, So the highest power of 23 is |
\$ 23^1 \$ |
6 |
Step |
The highest power of 3 is |
\$ 3^1 \$ |
7 |
Step |
The highest power of 7 is |
\$ 7^1 \$ |
8 |
Step |
Multiply the highest powers of each prime factor together |
\$ LCM = 23^1*3^1*7^1\$ |
9 |
Step |
After simplification we get |
\$ LCM = 23*3*7 \$ |
10 |
Step |
After simplification we get |
\$ LCM = 483\$ |
11 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
|
12 |
Choice.A |
This is not the correct answer because 493 is not divisible by 21 |
493 |
13 |
Choice.B |
This is incorrect as it does not satisfy the condition of being a multiple of both numbers |
473 |
14 |
Choice.C |
This is correct because it is the smallest common multiple of 23 and 21 |
483 |
15 |
Choice.D |
This is not the correct answer because 463 is neither divisible by 23 nor by 21 |
463 |
16 |
Answer |
Option |
C |
17 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
|
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