Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Least common multiple |
Grade: 6-a Lesson: S1-L3 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
Find the least commom multiple for the following numbers 6 and 15. |
|
2 |
Hint |
To find the least common multiple (LCM) of 6 and 15, you can use the prime factorization method. |
|
3 |
Step |
Prime factorization of 6: |
\$ 2^1*3^1\$ |
4 |
Step |
Prime factorization of 15: |
\$ 3^1*5^1 \$ |
5 |
Step |
Next, we identify the highest powers of each prime factor, So the highest power of 2 is |
\$ 2^1 \$ |
6 |
Step |
The highest power of 3 is |
\$ 3^1 \$ |
7 |
Step |
The highest power of 5 is |
\$ 5^1 \$ |
8 |
Step |
Multiply the highest powers of each prime factor together |
\$ LCM = 2^1*3^1*5^1\$ |
9 |
Step |
After simplification we get |
\$ LCM = 2*3*5 \$ |
10 |
Step |
After simplification we get |
\$ LCM = 30\$ |
11 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
|
12 |
Choice.A |
This is correct because it is the least common multiple of 6 and 15 |
30 |
13 |
Choice.B |
This is not correct. 16 is not a multiple of both 6 and 16 |
16 |
14 |
Choice.C |
This is not correct. 25 is not a multiple of both 6 and 15 |
25 |
15 |
Choice.D |
This is not correct because 32 is not the smallest multiple that is divisible by both 6 and 15 |
32 |
16 |
Answer |
Option |
A |
17 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
|
Copyright © 2020-2022 saibook.us Contact: info@saibook.us Version: 1.5 Built: 08-January-2024 08:10 PM EST