Lesson Example Discussion Quiz: Class Homework |
Step-1 |
Title: Least common multiple |
Grade: 6-a Lesson: S1-L3 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Find the least common multiple 45 and 69. |
|
2 |
Hint |
To find the least common multiple (LCM) of 45 and 69, you can use the prime factorization method. |
|
3 |
Step |
Prime factorization of 45: |
\$ 3^2 * 5^1 \$ |
4 |
Step |
Prime factorization of 69: |
\$ 3^1 * 23^1 \$ |
5 |
Step |
Next, we identify the highest powers of each prime factor, So the highest power of 3 is |
\$ 3^2 \$ |
6 |
Step |
The highest power of 5 is |
\$ 5^1 \$ |
7 |
Step |
The highest power of 23 is |
\$ 23^1 \$ |
8 |
Step |
Multiply the highest powers of each prime factor together |
\$ LCM = 3^2 * 5^1 * 23^1 \$ |
9 |
Step |
After simplification we get |
\$ LCM = 9 * 5 * 23 \$ |
10 |
Step |
After simplification we get |
\$ LCM = 1035 \$ |
11 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
|
12 |
Choice.A |
This statement is incorrect. 1045 divided by 69 equals 15 with a remainder, so it cannot be the least common multiple |
1045 |
13 |
Choice.B |
This is the correct answer because it is the smallest number that is evenly divisible by both 45 and 69 |
1035 |
14 |
Choice.C |
This is not divisible by 45 and leaves a remainder of 22. Therefore, it cannot be the least common multiple |
1025 |
15 |
Choice.D |
This is not correct because it does not include all the necessary prime factors |
1015 |
16 |
Answer |
Option |
B |
17 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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