Lesson Example Discussion Quiz: Class Homework |
Quiz At Home |
Title: Congruency of triangles(SAS) |
Grade: 10-a Lesson: S2-L5 |
Explanation: |
Quiz: at Home
Problem Id | Question |
---|---|
1 |
In the figure \$BG \bot DE\$, AC = CF and AB = CE. If BC \$120\$ and EF \$= 11m - 1\$, find the value of m. A) 20 B) 15 C) 11 D) 17 |
2 |
\$EB \bot AC\$, B is the mid-point of AC, \$\angle AEB = 30^\circ\$, find \$\angle BDE\$. A) \$100^\circ\$ B) \$45^\circ\$ C) \$50^\circ\$ D) \$60^\circ\$ |
3 |
ABCD is a square, E, F, G and H are the mid-points of AB, BC, CD and DA respectively. If DI \$16b - 40\$, IB = \$60 - 4b\$ and \$\angle BIF = 10b\$, Find \$\angle BEF\$. A) \$\angle BEF = 20^\circ\$ B) \$\angle BEF = 50^\circ\$ C) \$\angle BEF = 60^\circ\$ D) \$\angle BEF = 45^\circ\$ |
4 |
B is the mid-point of AC and ED, AB \$= 2b - 50\$, BC \$= 40 - b\$, \$\angle ABE = 30^\circ\$ and \$\angle AEB = 2b\$. Find \$\angle AEB\$. A) \$\angle AEB = 30^\circ\$ B) \$\angle AEB = 60^\circ\$ C) \$\angle AEB = 70^\circ\$ D) \$\angle AEB = 45^\circ\$ |
5 |
E is the mid-point of BC, FE perpendicular to BC, BF \$= 16M\$, FC \$= 64\$, \$\angle EFC = 70^\circ\$ and \$\angle FCE = 5M\$. Find sum of \$\angle FCE\$ and \$\angle FEB\$. A) \$\angle AEB = 110^\circ\$ B) \$\angle AEB = 130^\circ\$ C) \$\angle AEB = 80^\circ\$ D) \$\angle AEB = 150^\circ\$ |
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