1

Problem

The perimeter of a rectangle is 54 inches, and the length of the rectangle is double its width. Find the length and width.

2

Step

According to the information given, the length of the rectangle is double its width, which can be expressed as:

l = 2w

3

Step

The perimeter (P) of the rectangle is

54 inches

4

Formula

Perimeter of rectangle P = 2(l + w).

5

Step

Now, we can substitute the expression for l from above into the perimeter formula:

54 = 2(2w + w)
54 = 2(3w)

6

Step

After simplification

54 = 6w

7

Step

To solve the equation, you need to divide 6 on both sides.

\$54/6 = (6w)/6\$
w = 9

8

Hint

The width of the rectangle is 9 inches.we can find the length (l) using the relationship l= 2w:

l = 2(9) = 18

9

Step

Length (l) is

18 inches

10

Solution

So, the rectangle’s Length and width are 18 inches and 9 inches.

11

Sumup

Please summarize steps

Choices

12

Choice-A

The given value mismatches the correct answer, revealing inaccuracies in the rectangle’s length and width and an incorrect choice

Wrong Length = 20 inches, Width = 10 inches

13

Choice-B

The given value mismatches the correct answer, revealing inaccuracies in the rectangle’s length and width and an incorrect choice

Wrong Length = 16 inches, Width = 9 inches

14

Choice-C

The provided value matches the answer, confirming it as the accurate length and width of the rectangle, making it the correct choice

Correct Length = 18 inches, Width = 9 inches

15

Choice-D

The given value mismatches the correct answer, revealing inaccuracies in the rectangle’s length and width and an incorrect choice

Wrong Length = 16 inches, Width = 8 inches

16

Answer

Option

C

17

Sumup

Please summarize choices