1

Problem

A square has twice the perimeter of another square. If the smaller square has a side length of 4 inches, what is the side length of the larger square?

2

Hint

According to the information given, the larger square has twice the perimeter of the smaller square.

3

Clue

The perimeter(P) of a square is given by the formula P = 4s.

4

Step

Perimeter of the smaller square

\$P = 4s = 4 \times 4 = 16\$ inches

5

Step

Now, according to the problem, the larger square has twice this perimeter:

6

Hint

\$"Perimeter of the larger square" = 2 \times "Perimeter of the smaller square"\$.

7

Step

Perimeter of the larger square

\$P = 2 \times 16 = 32\$ inches

8

Step

Now, we know the perimeter(P) of the larger square is 32 inches. To find the side length of the larger square.

9

Formula

Perimeter of a square \$P = 4 \times s\$.

10

Step

Substitute the values

\$32 = 4 \times s\$

11

Step

Now, divide both sides by 4 to solve for s

\$(32)/4 = (4s)/4\$
s = 8

12

Solution

So, the side length of the larger square is 8 inches.

13

Sumup

Please summarize steps

Choices

14

Choice-A

The provided option aligns with the answer, indicating its correctness; therefore, it is the correct answer

Correct 8 inches

15

Choice-B

The provided option doesn’t align with the correct answer, making it an incorrect choice in this context

Wrong 10 inches

16

Choice-C

The provided option doesn’t align with the correct answer, making it an incorrect choice in this context

Wrong 12 inches

17

Choice-D

The provided option doesn’t align with the correct answer, making it an incorrect choice in this context

Wrong 20 inches

18

Answer

Option

A

19

Sumup

Please summarize choices