Step-4

Title: Perpendiculer Lines

Grade: 6-a Lesson: S2-L8

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Find the equation of the line passing through (8, −2) and perpendicular to 2x + 6y = 1.

2

Step

The given values are

⇒ \$"x"_1 = 8\$
⇒ \$"y"_1 = -2\$
⇒ equation = 2x + 6y = 1

3

Formula

To find its slope, we can rewrite it in the slope-intercept form

⇒ y = mx + b
where m = slope

4

Step

Rewrite the equation in the form of slope-intercept form

6y = −2x + 1

5

Step

After simplification

⇒ \$"y" = (-2/6) "x" + 1/6\$
⇒ \$"y" = (-1/3) "x" + 1/6\$

6

Hint

So, the slope of the given line is \$-1/3\$.

7

Formula

The slope-point form of the equation of a line:

\$"y" − "y"_1​ = "m"("x" − "x"_1​\$)

8

Step

Plugging in the values in the formula

y − (−2) = 3(x − 8)

9

Step

Simplify the equation

y + 2 = 3x - 24

10

Step

Now, isolate y

y = 3x − 26

11

Step

So, the equation of the line passing through (8, −2) and perpendicular to 2x + 6y = 1 is y = 3x − 26.

12

SumUp

Can you summarize what you’ve understood in the above steps?

13

Choice.A

This is correct because it have the correct slope for a line perpendicular to the given line

y = 3x − 26

14

Choice.B

This is not correct because it does not have the correct slope for a line perpendicular to the given line

y = x − 26

15

Choice.C

This is not correct because it has a positive slope, while we need a line with a slope of 3

y = 3x + 26

16

Choice.D

This is not correct because it does not have the correct slope for a line perpendicular to the given line

y = x + 26

17

Answer

Option

A

18

SumUp

Can you summarize what you’ve understood in the above steps?


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