Lesson Example Discussion Quiz: Class Homework |
Example |
Title: Parallel Lines |
Grade: 6-a Lesson: S2-L7 |
Explanation: The best way to understand geometry is by looking at some examples. Take turns and read each example for easy understanding. |
Examples:
Find the equation of a straight line is passing through (5, 6) and parallel to the line 4x - y + 8 = 0.
Step 1a
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The slope of a line is 4x - y + 8 = 0. |
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Explanation: Rearrange 4x - y + 8 = 0 to y = 4x + 8 in slope-intercept form. The slope (m) is 4. |
Step 1b
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To find a line parallel to the original, it must have the same slope, represented by "m", which, in this case, is 4. |
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Explanation: Since you want to find a line parallel to the original line, it will have the same slope, which is m = 4. |
Step 1c
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Using the slope (m = 4) and the point (5, 6), apply the point-slope form to discover the equation of the new line. |
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Explanation: Now that you have the slope (m = 4) and a point (5, 6), you can use the point-slope form of the line equation to find the equation of the new line: y - y1 = m(x - x1). |
Step 1d
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Substituting the values:
y - 6 = 4 (x - 5) |
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Explanation:
Now plug the values into the equation(x1, y1) = (5, 6) and m = 4. |
Step 1e
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Move numbers without variables to the right side:
y = 4x - 20 + 6 |
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Explanation:
In this step, Enhance and simplify the equation: |
Step 1f
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So, the equation of the line passing through the point(5, 6) and parallel to the line 4x - y + 8 = 0 is y = 4x - 14. |
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Explanation:
The line that goes through the point (5, 6) and is parallel to the line 4x - y + 8 = 0 can be expressed as |
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