If the perimeter of an equilateral triangle is 28 units. Then find its area.

Area of an equilateral triangle is

\$(\sqrt(3) / 4) \times s^2 \$

The perimeter of an equilateral triangle is

28 units

An equilateral triangle has all sides equal, you can find the length of one side (s) by dividing the perimeter by 3.

s = Perimeter / 3

Substitute the values

s = \$28 / 3 \$

After simplification, the side value we get

s = 9.33 units

Now that you know the length of one side (s),so you can calculate the area using the formula

Area = \$s^2 * (\sqrt(3) / 4)\$

Substitute the values

A = \$(9.33)^2 * (\sqrt(3) / 4)\$

After simplification

A = \$(87.1121 * \sqrt(3)) / 4\$

Then the area of an equilateral triangle is

\$21.77\(sqrt3)(cm)^2\$

Can you summarize what you’ve understood in the above steps?

The chosen option doesn’t align with the correct answer; the equilateral triangle’s area doesn’t match, making it incorrect

\$21(sqrt2)(cm)^2\$

The correct answer corresponds to the equilateral triangle’s area being equal to the selected option

\$21.77(sqrt3)(cm)^2\$

The chosen option doesn’t align with the correct answer; the equilateral triangle’s area doesn’t match, making it incorrect

\$11.65(sqrt3)(cm)^2\$

The chosen option doesn’t align with the correct answer; the equilateral triangle’s area doesn’t match, making it incorrect

\$20.11(sqrt3)(cm)^2\$

Option

B

Can you summarize what you’ve understood in the above steps?