Lesson Example Discussion Quiz: Class Homework |
Example |
Title: Area of Square |
Grade: 6-a Lesson: S1-L5 |
Explanation: The best way to understand geometry is by looking at some examples. Take turns and read each example for easy understanding. |
Examples:
A square field has a perimeter of 240 m. What is the length of its side and area?
Step 1a
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The perimeter(P) of a square is P = \$4 times s\$ The given perimeter of a square is 240 m. |
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Explanation: The perimeter of a square is calculated by multiplying the length of one of its sides by 4(p = 4s). If the given perimeter of a square is 240 m. |
Step 1b
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Solve for the side length(s): Divide both sides of the equation by 4: s = \$240 / 4\$ s = 60 meters So, the length of each side of the square field is 60 meters. |
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Explanation: To determine the length (s) of each side of a square field. s = \$240/4\$. , First, divide 240 by 4, which gives you 60.Therefore, the length of each side of the square field is 60 meters. |
Step 1c
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Now, find the area of the square and use the formula for the area of a square: \$Area(A) = s^2\$ substitute the values A = \$(60)^2\$\$(60 times 60)\$ = 3600 sq.mtrs |
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Explanation: Now, let’s calculate the area of a square using the formula A = \$s^2\$, where A is the area and s is the length of one side. s = \$(60)^2\$ is 3600 sq.mtrs |
Step 1d
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Therefore, the area of a square is 3600 sq.meters. |
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Explanation: The area of a square is 3600 square meters. |
The diagonal of a square is 20 units. Find the area & length of each side of the square.
Step 2a
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In this case, let’s assume that each side of the square has a length of x units. Diagonal of a square is 20 units. |
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Explanation: In this case, let’s assume that each side of the square has a length of x units. The diagonal of the square is 20 units. |
Step 2b
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Applying the Pythagorean theorem, we have: \$x^2 + x^2 = 20^2\$ = \$2x^2 = 400\$ Dividing both sides by 2, we have: \$x^2 = 200\$ |
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Explanation: When applying the Pythagorean theorem to the equation \$x^2 + x^2 = 20^2\$, we can simplify it to \$2x^2 = 400\$, and then to \$x^2\$ = 200. |
Step 2c
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Taking the square root of both sides, we find: x = \$\sqrt 200\$ Simplifying further, we have: x = \$\sqrt (100) \times 2\$ = \$10 \sqrt 2\$ Therefore, each side of a square is \$10 \sqrt 2\$ units. |
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Explanation: Taking the square root of 200, we get x = \$10 \sqrt 2\$. Each side of a square measures 10 multiplied by the square root of 2 units. |
Step 2d
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Now, we have to find the area of a square Area = \$"side" times "side"\$ = \$10 \sqrt 2 times 10 \sqrt 2\$ = 200 sq.units Hence, the area of a square is 200 sq.units |
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Explanation: Let’s find the area of a square. The formula is \$"side" times "side"\$, which means in this case it’s \$10 \sqrt 2 times 10 \sqrt 2\$. Therefore, the area is 200 sq.units. |
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