The perimeter of a rectangle is 54 inches, and the length of the rectangle is double its width. Find the length and width.

According to the information given, the length of the rectangle is double its width, which can be expressed as:

l = 2w

The perimeter (P) of the rectangle is

54 inches

Perimeter of rectangle

P = 2(l + w)

Now, we can substitute the expression for l from above into the perimeter formula:

54 = 2(2w + w)

54 = 2(3w)

54 = 6w

To solve the equation, you need to divide 6 on both sides.

\$54/6\$ = \$(6w)/6\$

w = 9

The width of the rectangle is 9 inches.we can find the length (l) using the relationship l = 2w :

l = 2(9) = 18

Length (l) is

18 inches

So, the correct option is:

Option C: Length = 18 inches, Width = 9 inches.

Can you summarize what you’ve understood in the above steps?

The given value mismatches the correct answer, revealing inaccuracies in the rectangle’s length and width and an incorrect choice

Length = 20 inches, Width = 10 inches

The given value mismatches the correct answer, revealing inaccuracies in the rectangle’s length and width and an incorrect choice

Length = 16 inches, Width = 9 inches

The provided value matches the answer, confirming it as the accurate length and width of the rectangle, making it the correct choice

Length = 18 inches, Width = 9 inches

The given value mismatches the correct answer, revealing inaccuracies in the rectangle’s length and width and an incorrect choice

Length = 16 inches, Width = 8 inches

Option

C

Can you summarize what you’ve understood in the above steps?