Lesson Example Discussion Quiz: Class Homework |
Example |
Title: Perimeter of Rectangle |
Grade: 6-a Lesson: S1-L4 |
Explanation: The best way to understand geometry is by looking at some examples. Take turns and read each example for easy understanding. |
Examples:
Mike is creating a fence around his yard for his new puppy.The perimeter of the yard is 94 feet and the length of the yard is 32 feet. What is the width of the yard ?
Step 1a
|
|
Given that the Perimeter(p) is 94 feet length(l) is 32 feet The formula for the perimeter of a rectangle is: Perimeter (P) = 2 × (Length(l) + Width(w)) |
![]() . |
Explanation: The perimeter of the given fence is 94 meters, and the length is 34 meters. |
Step 1b
|
|
We now need to determine the length of l by using formula : 94 = 2(32 + w) ⇒ 94 = 64 + 2w ⇒ 94 - 64 = 2w ⇒30 = 2w |
|
Explanation: We need to determine the width of w by solving the equation 94 = 2(34 + w). After simplification, we get 30 = 2w. |
Step 1c
|
|
Now divide 2 on both sides \$30/2 = (2w)/2\$ ⇒ w = 15 So, the length of the rectangle is 15 feet. |
|
Explanation: After doing the calculation, it was determined that the width of the fence is 15 feet. |
Copyright © 2020-2024 saibook.us Contact: info@saibook.us Version: 1.5 Built: 09-January-2023 08:10 PM EST