Step-4

Title: Volume of Pyramid

Grade: 4-a Lesson: S3-L7

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

The volume of a triangular pyramid with a slant height of 11 cm is 567 cubic cm and the height is 9 cm. Could you find the length of its base?

2

Step

The given values of volume, height and slant height are

V = 567 \$cm^3\$
h = 9 cm
l = 11 cm

3

Formula

The volume of the Triangular pyramid is

V = \$1/3 times a times h\$

4

Formula

The area of the base of the pyramid equals half of the product of the base and the height

a = \$1/2 times b times h\$

5

Step

Substitute the "a" value in the volume formula

V = \$1/3 times (1/2 times b times h) times h\$

6

Step

Substitute the given values in the above equation, we get

567 = \$1/3 times (1/2 times b times 9) times 9\$

567 = \$1/6 times b times 81\$

7

Step

After simplification, we get

567 = \$81/6 times b\$

567 = \$13.5 times b\$

\$567/13.5\$ = b

b = 42

8

Step

The base length of a triangular pyramid is 42 cm.

9

SumUp

Can you summarize what you’ve understood in the above steps?

10

Choice.A

The received answer for this problem doesn’t align with option, making it incorrect

53 cm

11

Choice.B

The answer for this problem is equivalent to the one provided in option, making it the correct choice

42 cm

12

Choice.C

The received answer for this problem doesn’t align with option, making it incorrect

66 cm

13

Choice.D

The received answer for this problem doesn’t align with option, making it incorrect

69 cm

14

Answer

Option

B

15

SumUp

Can you summarize what you’ve understood in the above steps?


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