The cone has a base diameter of 13 feet and a height three times the diameter. Find the surface area of the cone.(π = 3.14).

The given values are

d = 13 ft, and height is three times of diameter

The surface area of a cone is

\$"Surface area" = πr(r + l)\$

The radius is equal to diameter divided by 2

\$r = d/2\$

Now plug the values into the hint

\$r = 13 / 2\$

r = 6.5

Height is three times the diameter

\$ H = 3 times 13\$

h = 39 ft

Now, we need to find the slant height (ll). This can be found using the Pythagorean theorem:

\$l^2 = r^2 + h^2\$

Now plug the values into the formula

\$l^2 = (6.5)^2 + 39^2\$

After simplification

\$l^2 = 42.25 + 1521\$

After simplification

\$l^2 = 1563.25\$

After simplification

l = 39.53

Now, substitute the values into the surface area formula:

\$"Surface area" = π times 6.5 times (6.5 + 39.54)\$

After make it simpler

\$"surface are"a" = π times 6.5 times 46.04\$

After simplification

Surface area = 939.67 sq.ft

The surface area of a cone is 939.67 sq,ft

Can you summarize what you’ve understood in the above steps?

The given option is incorrect, deviating from the provided choices, and inaccurately represents the cone surface are

879.63 sq.feet

The answer aligns with this option, confirming that it is the accurate value for a cone surface area

939.67 sq.feet

The given option is incorrect, deviating from the provided choices, and inaccurately represents the cone surface are

909.66sq.feet

The given option is incorrect, deviating from the provided choices, and inaccurately represents the cone surface are

987.63 sq.feet

Option

B

Can you summarize what you’ve understood in the above steps?