Lesson Example Discussion Quiz: Class Homework |
Step-1 |
Title: Surface area of 3D shapes(Cube, cuboid, Cone) |
Grade: 4-a Lesson: S3-L1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
The radius of a cone is 18 inches and the slant height of a cone is 11 inches. Using the total surface area formula of the cone calculate the surface area of the cone. (π = 3.14) |
|
2 |
Step |
The given values are |
r = 18 inches and h = 11 inches |
3 |
Formula |
Total surface area of cone |
Total surface area = πr(r + l) |
4 |
Step |
Now plug the values into the formula |
\$"Total surface area" = π times 18(18 + 11)\$ |
5 |
Step |
After simplification |
\$"Total surface area" = 3.14 times 18 times 29\$ |
6 |
Step |
After simplification |
\$"Total surface area" = 3.14 times 522\$ |
7 |
Step |
After simplification |
Total surface area = 1639.08 sq.in |
8 |
Step |
Therefore, the surface area of the cone is approximately 1639.08 sq.in. |
|
9 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
10 |
Choice.A |
The answer you received for this problem doesn’t match the option; hence, it is incorrect |
1639.80 sq.in |
11 |
Choice.B |
The answer you received for this problem doesn’t match the option; hence, it is incorrect |
1639.12 sq.in |
12 |
Choice.C |
The answer you received for this problem doesn’t match the option; hence, it is incorrect |
1639.808 sq.in |
13 |
Choice.D |
The correct option provides an equivalent answer to this problem |
1639.08 sq.in |
14 |
Answer |
Option |
D |
15 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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