Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Area of Triangle(Based on Angles) |
Grade: 4-a Lesson: S2-L6 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Calculate the area of an obtuse-angled triangle with side lengths of 8 units, 10units, and an included angle of 120 degrees. |
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2 |
Step |
Given that the sides of a triangle are 8 units and 10 units. |
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3 |
Step |
Given angle is 120° |
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4 |
Formula |
The area of an obtuse-angled triangle, you can use the formula: |
\$1/2 \times "a" \times "b" \times sin(C)\$ |
5 |
Step |
Now plug the values into the formula |
A = \$1/2 \times 8 \times 10 \times sin(120°)\$ |
6 |
Step |
After simplification the value we get |
A = \$1/2 \times 80 \times sin(120°)\$ |
7 |
Clue |
sin 120° = \$\sqrt(3)/2\$ |
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8 |
Step |
Now place the sin120° value. |
A = \$1/2 \times 80 \times \sqrt(3)/2\$ |
9 |
Step |
After simplification the value we get |
A = \$20 \sqrt(3)\$ |
10 |
Step |
So, the area of the obtuse-angled triangle is \$ 20 \sqrt 3\$ square units. |
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11 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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12 |
Choice.A |
The received answer for this problem doesn’t align with option 22\$\sqrt 3\$ sq. units, making it incorrect |
22\$\sqrt 3\$ sq.units |
13 |
Choice.B |
The answer for this problem is equivalent to the one provided in option 20\$\sqrt 3\$ sq.units, making it the correct choice |
20\$\sqrt 3\$ sq.units |
14 |
Choice.C |
The received answer for this problem doesn’t align with option 10\$\sqrt 3\$ sq. units, making it incorrect |
10\$\sqrt 3\$ sq.units |
15 |
Choice.D |
The received answer for this problem doesn’t align with option 20\$\sqrt 2\$ sq. units, making it incorrect |
20\$\sqrt 2\$ sq.units |
16 |
Answer |
Option |
B |
17 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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