SaiBook.us Geometry

Lesson Example Discussion Quiz: Class Homework

Example

Title: Area of Triangle(Based on Sides)

Grade: 4-a Lesson: S2-L5

Explanation: The best way to understand geometry is by looking at some examples. Take turns and read each example for easy understanding.

Examples:

Find the area of a triangle whose length of each side is 3 inches , 3 inches and 4 inches.

Step 1a

Given sides of a triangle is a = 3 inches,b = 3 inches, c = 4 inches.

Now,we can use Heron’s formula to find the area of the triangle.

Area of triangle = \$\sqrt(s(s – a)(s – b)(s – c)\$

$1a$

Explanation: Given the sides of a triangle as a = 3 inches, b = 3 inches, and c = 4 inches, we can use Heron’s formula to determine the area of the triangle.The formula is as follows: Area of triangle = \$\sqrt(s(s – a)(s – b)(s – c)\$

Step 1b

Where s is the semi-perimeter of the triangle, which is calculated as: s = \$(a + b + c)/2\$.

By substituting the values of a, b, and c into the formula, we can easily calculate the area of the triangle. s = \$10/2\$ = 5 inches

Explanation: First we find the s value

s = \$(a + b + c)/2\$

s = \$(3 + 3 + 4)/2\$

s = \$10/2\$

s = 5

Step 1c

Now substitute the values A = \$\sqrt((10(10-3)(10-3)(10-4))\$ = \$\sqrt(10(7)(7)(6))\$

A = \$\sqrt(2940)\$ Approximately 54 sq.inches

Explanation: Substitute the given values: A = \$\sqrt((10(10-3)(10-3)(10-4))\$

A = \$\sqrt((10(7)(7)(6))\$.

This yields A = \$\sqrt(2940)\$, which is approximately 54 sq. inches.

Step 1d

So, the area of the triangle is 54 sq.inches

Explanation: The area of the triangle is 54 square inches.