Lesson Topics Discussion Quiz: Class Homework |
Steps-1 |
Title: Solve an Equation with Multiplication and Division |
Grade 6+ Lesson s3-l6 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
If 2(c + 4) - 3 = 3(2c - 1), what is the value of c? |
|
2 |
Step |
The given equation |
2(c + 4) - 3 = 3(2c - 1) |
3 |
Step |
let’s first distribute the numbers outside the parentheses: |
2 × c + 2 × 4 − 3 = 3 × 2c − 3 × 1 |
4 |
Step |
Simplify each side: |
2c + 8 − 3 = 6c − 3 |
5 |
Step |
Combine like terms: |
2c + 5 = 6c − 3 |
6 |
Step |
To isolate the variable terms on one side, let’s subtract 2c from both sides: |
2c − 2c + 5 = 6c − 2c − 3 5 = 4c - 3 |
7 |
Step |
Add 3 to both sides: |
5 + 3 = 4c − 3 + 3 8 = 4c |
8 |
Step |
Finally, to solve for c, divide both sides by 4: |
\$ 8/4 = (4c)/4 \$ |
9 |
Step |
After simplification |
2 = c ⇒ c = 2 |
10 |
Solution |
So, the solution to the equation is c = 2. |
|
11 |
Sumup |
Please Summarize Problem, Hint, Clue, Formula and Steps |
|
Choices |
|||
12 |
Choice-A |
If we substitute c = 5 into the original equation, the left side does not equal the right side, so c = 5 is not a solution |
Wrong 5 |
13 |
Choice-B |
Substituting c = 4 into the equation, we find that the equation is not balanced, so c = 4 is incorrect |
Wrong 4 |
14 |
Choice-C |
Plugging in c = 3 into the equation, it doesn’t hold true, so c = 3 cannot be a possible solution |
Wrong 3 |
15 |
Choice-D |
This step is correct, as we have verified that c equals 2 |
Correct 2 |
16 |
Step |
Option |
D |
17 |
Sumup |
Please Summarize Choices |
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