Lesson Topics Discussion Quiz: Class Homework |
Steps-5 |
Title: Product and Quotient of power rule & zero exponent rule |
Grade 6+ Lesson s3-l4 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Quiz: Discussion Step
| Id | Type | Name | Note |
|---|---|---|---|
1 |
Problem |
Simplify the expression using the Power of a Product Rule: \$ (3x 3y)^2 \$ |
|
2 |
Step |
The given expression |
\$ (3x 3y)^2 \$ |
3 |
Formula |
Apply the Power of a Product Rule, which states that \$ (ab)^n = a^n \times b^n \$. |
|
4 |
Hint |
Apply the rule to the expression: \$ (3x 3y)^2 = 3^2 \times x^2 \times 3^2 \times y^2 \$. |
|
5 |
Step |
Now, we can simplify: |
\$ (3x 3y)^2 = 9 \times x^2 \times 9 \times y^2 \$ |
6 |
Step |
Now, we can simplify further: |
\$ (3x 3y)^2 = 81x^2 y^2 \$ |
7 |
Solution |
Thus, \$ (3x 3y)^2 \$ simplifies to \$ 81(x^2) (y^2) \$. |
|
8 |
Sumup |
Please Summarize Problem, Hint, Clue, Formula and Steps |
|
Choices |
|||
9 |
Choice-A |
This choice is incorrect, the correct coefficient is 81, not 18 |
Wrong \$ 18 (x^2) (y^2) \$ |
10 |
Choice-B |
This choice is incorrect, the coefficient should be 81, not 181, and the exponent of y is positive, not negative |
Wrong \$ 181 (x^2) (y^-2) \$ |
11 |
Choice-C |
This choice is incorrect, the coefficient should be 81, not 92, and the exponent of y is 2, not 3 |
Wrong \$ 92 (x^2) (y^3) \$ |
12 |
Choice-D |
This option matches the simplified expression \$ 81(x^2) (y^2)\$ |
Correct \$ 81 (x^2) (y^2) \$ |
13 |
Step |
Option |
D |
14 |
Sumup |
Please Summarize Choices |
|
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