Lesson Example Discussion Quiz: Class Homework |
Example |
Title: Test2 |
Grade: 8-b Lesson: S1-P2 |
Explanation: The best way to understand algebra is by looking at some examples. Take turns and read each example for easy understanding. |
Examples:
Simplify the following expression: \$ (3u\sqrt(36v^2)) / (12\sqrt(100uv)) \$.
Step 1a
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Simplify inside the square roots: \$ \sqrt 36v^2 = 6v \$(since \$ \sqrt 36 = 6 \$) ⇒ \$ \sqrt100uv = 10\sqrtuv \$ So the expression becomes: \$ 3u 6v \div 12(10\sqrtuv) \$ |
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Explanation: We simplified the expressions inside the square roots and then substituted these simplified forms into the given expression. |
Step 1b
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Simplify the constants: \$ 3 \times 6 = 18 \$ ⇒ \$ 12 \times 10 = 120 \$ Substitute these values: \$ 18uv \div 120(\sqrt100uv) \$ |
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Explanation: We simplified the numbers and then used these simplified values in the expression. |
Step 1c
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Simplify the fraction (reduce the fraction): Simplify \$ 18uv \div 120(\sqrt100uv) \$ Divide both numerator and denominator by 6: \$ 3uv \div 20\sqrtuv \$ Therefore, the simplified expression is \$ 3uv \div 20\sqrtuv \$. |
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Explanation: After reducing the fraction, we determine the final result. |
Calculate the sum of the cube root of 64 and the square root of 25?
Step 2a
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The given cube root = 64 and squre root = 25. The cube root of 64 is \$root(3)64 = 4\$, becuase \$4 times 4 times 4\$ = 64. The square root of 25 is \$\sqrt(25) = 5\$, beacuse \$5 times 5\$ = 25. So, the sum of the cube root of 64 and the square root of 25 is 4 + 5 = 9. |
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Explanation: Find the cube root and square root of a given number, then add them together. |
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