Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Dividing Radicals |
Grade: 8-b Lesson: S1-L8 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
Dividing the following radical expression: \$ (6\sqrt((2)\sqrt(3))) / (\sqrt(6))\$. |
|
2 |
Step |
The given radical expression is |
\$ (6\sqrt((2)\sqrt(3))) / (\sqrt(6))\$ |
3 |
Step |
Simplify first \$\sqrt(6)\$: |
\$\sqrt(6) = \sqrt(2 .3) = \sqrt(2) . \sqrt(3)\$ |
4 |
Step |
Substitute and simplify the numerator \$ 6\sqrt((2) \sqrt(3))\$: |
\$6 \(sqrt((2). (3)^(1/2))) = 6 (2 .3^(1/2))^(1/2)\$ \$6 . 2^(1/2) . (3^(1/2))^(1/2) = 6 . 2^(1/2). 3^(1/4)\$ |
5 |
Step |
Combine and simplify: |
\$ (6\sqrt((2)\sqrt(3))) / (\sqrt(6)) = (6. 2^(1/2). 3^(1/4)) / (\sqrt(2) . \sqrt(3))\$ \$= (6 . 3^(1/4)) / (3^(1/2))\$ \$= 6 . 3^(1/4 - 1/2)\$ \$= 6 . 3^(- 1/4)\$ \$= 6 / 3^(1/4)\$ |
6 |
Step |
Make it simplify |
\$(2 . 3) / 3^ (1/4)\$ \$2 root(4) (3^3)\$ |
7 |
Step |
So, therefore the simplified expression is \$ 2 root(4) (3^3)\$. |
|
8 |
Choice.A |
It is missing the factor of 2, which is necessary for correctly simplifying the original expression. Hence, option A is not equivalent to the given expression |
\$ root(4)(3^3)\$ |
9 |
Choice.B |
Option B suggests \$ 2 root(3)(4^3)\$ which involves a cube root and \$4^3\$ whereas the simplified form involves a fourth root and \$3^3\$ |
\$ 2 root(3)(4^3)\$ |
10 |
Choice.C |
Option C is correct: It accurately simplifies the division of radicals given in the original expression |
\$ 2 root(4)(3^3)\$ |
11 |
Choice.D |
It does not represent the correct simplification based on the rules of dividing radicals |
\$ root(3)(4^3)\$ |
12 |
Answer |
Option |
C |
13 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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