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Step-3

Title: Addition of equation to find variable

Grade: 7-a Lesson: S1-L4

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step	Type	Explanation	Answer
1	Problem	Solve the equation: 4 a + 20 = 6 a + 10
2	Step	Moving constant terms to right side and variable terms to the left side we get	4 a - 6 a = 10 - 20
3	Step	Seperate variable	( 4 - 6 ) a = 10 - 20
4	Step	After Subtraction we get	\$ -2a = -10 \$
5	Step	Dividing with -2 on both sides	\$ (\cancel(-2)a)/\cancel(-2) = \cancel(-10)^5/\cancel(-2)^1 \$
6	Step	After Division	a = 5
7		Answer	C

Step

Type

Explanation

Answer

Problem

Solve the equation:
4 a + 20 = 6 a + 10

Step

Moving constant terms to right side and variable terms to the left side we get

4 a - 6 a = 10 - 20

Step

Seperate variable

( 4 - 6 ) a = 10 - 20

Step

After Subtraction we get

\$ -2a = -10 \$

Step

Dividing with -2 on both sides

\$ (\cancel(-2)a)/\cancel(-2) = \cancel(-10)^5/\cancel(-2)^1 \$

Step

After Division

a = 5

Answer

Tutor: Questions

Seq	Type	Question
1	Problem	What did you learn from this problem?
2	Clue	What did you learn from the clues?
3	Hint	What did you learn from the Hints?
4	Step	What did you learn from the Steps?
5	Step	How can we improve the Steps?

Seq

Type

Question

Audio

Problem

What did you learn from this problem?

Clue

What did you learn from the clues?

Hint

What did you learn from the Hints?

Step

What did you learn from the Steps?

Step

How can we improve the Steps?