Step 1a

The given number is \$\sqrt 3\$. Real numbers include all rational and irrational numbers. Since \$ \sqrt(3) \$ is a non-negative, non-repeating, non-terminating decimal, it is a real number.

Explanation: Here we write the given data. Determining whether a given value is a real number or not.

Step 1b

Assume \$\sqrt(3) \$ is rational.
Square both sides of \$\sqrt(3) = q/p \$ to obtain 3 = \$ p^2 / q^2 \$.
Deduce that p and q must both be divisible by 3, leading to a contradiction.

Explanation: Verifying it as an irrational number. Therefore, \$ \sqrt(3) \$ is both a real number and an irrational number.

Step 2a

(+3) × (+2) = +6

(-3) × (-2) = +6

(+3) × (-2) = -6

(-3) × (+2) = -6

(+3) × 0 = 0

(-3) × 0 = 0

Explanation: Here the sign rules for multiplication were applied.