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Lesson Example Discussion Quiz: Class Homework

Step-1

Title: Ratios

Grade: 8-a Lesson: S2-L4

Explanation: Let us verify the answer here with the steps.

Description:

Step	Type	Explanation	Answer
1	Problem	In a mixture of 60 liters, the ratio of lemon solution to salt solution is 1:2. What is the amount of lemon solution to be added if the ratio has to be 2:1?
2	Hint	Operator used : Ratio	:
3	Step	Amount of mixture	\$60\$liters
4	Step	The ratio of lemon solution to salt solution	\$1:2\$
5	Step	Amount of lemon solution in the mixture	\$1/(1 + 2) \times 60\$ ⇒ \$1/3 \ times 60\$ ⇒ 20 litres
6	Step	So, salt solution present in the mixture	\$60 - 20 = 40 litres\$
7	Step	Let the amount of lemon solution to be added be	'x' litres
8	Step	Then	\$"lemon solution"/"salt solution" = 2/1\$ ⇒ \$(20 + x)/40 = 2/1\$ ⇒ \$20 + x\$ = 40 x 2 ⇒ \$20 + x = 80\$ ⇒ \$x = 80 - 20\$ ⇒ \$x = 60\$
9		=	\$x=60\$
10	Step	Thus, amount of lemon solution to be added if the ratio has to be 2:1	60 litres

Step

Type

Explanation

Answer

Problem

In a mixture of 60 liters, the ratio of lemon solution to salt solution is 1:2. What is the amount of lemon solution to be added if the ratio has to be 2:1?

Hint

Operator used : Ratio

Step

Amount of mixture

\$60\$liters

Step

The ratio of lemon solution to salt solution

\$1:2\$

Step

Amount of lemon solution in the mixture

\$1/(1 + 2) \times 60\$

⇒ \$1/3 \ times 60\$

⇒ 20 litres

Step

So, salt solution present in the mixture

\$60 - 20 = 40 litres\$

Step

Let the amount of lemon solution to be added be

'x' litres

Step

Then

\$"lemon solution"/"salt solution" = 2/1\$

⇒ \$(20 + x)/40 = 2/1\$

⇒ \$20 + x\$ = 40 x 2

⇒ \$20 + x = 80\$

⇒ \$x = 80 - 20\$

⇒ \$x = 60\$

\$x=60\$

Step

Thus, amount of lemon solution to be added if the ratio has to be 2:1

60 litres