A shopkeeper purchased 297 g 500 mg of orange. Later on, he found that 98 g 340 mg of oranges were rotten. Find the quantity of oranges in good condition.

Total quantity of oranges purchased is

297 g 500 mg

Weight of rotten oranges is

98 g 340 mg

First, ensure the units are consistent. Convert the grams and milligrams into a single unit (either grams or milligrams) for ease of calculation

1 g = 1000 mg

After converting gms to mg the total quantity purchased is

297 g = 297,000 mg

500 mg = 500 mg

After converting gms to mg the weight of rotten oranges is

98 g = 98,000 mg

340 mg = 340 mg

Now, subtract the weight of the rotten oranges from the total purchased:

Total quantity - Weight of rotten oranges = Quantity of oranges in good condition

Values substituted in the formula

\$297,500"mg" − 98,340"mg" = 199,160"mg"\$

The quantity of oranges in good condition is 199,160 milligrams. If we prefer the answer in kilograms:

\$199,160"mg" times (0.000001"kg")/"mg" (1"mg" = 0.000001"kg")\$

⇒ \$0.19916 "kg"\$

Therefore, the quantity of oranges in good condition is 0.19916 kilograms.

Answer

D