Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Binomial distribution |
Grade: 9-a Lesson: S4-L4 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
The probability of a customer ordering the colour of a particular model of new car in silver is 0.2. Find the probability that in next 10 random orders there will be at most 8 orders in silver.? |
|
2 |
Clue |
Probability that in next 10 random orders there will be at most 8 orders in silver |
P(X≤8) |
3 |
Formula: |
Probability P(x)=\$n_(C_x) p^x q^(n-x)\$ |
|
4 |
Step |
From the given data |
n= 10,p=0.2 |
5 |
Step |
Finding the value of q |
q = 1-p q = 1-0.2 ⇒ q=0.8 |
6 |
Step |
P(X≤8) |
1-P(x>8) |
7 |
Step |
P(X≤8) |
1-(P(x=9) + P(x=10)) |
8 |
Step |
Substitute all the values in P(X≤8) |
\$1 - 10_(C_9)(0.4)^9(0.6)^(10-9) + 10_(C_10)(0.4)^10(0.6)^(10-10)\$ |
9 |
Hint |
\$n_(C_x) = (n!)/((n-x)!x!)\$ |
|
10 |
Step |
P(X≥4) |
\$1 - (10!)/((10-9)!9!) (0.4)^9 (0.6)^9 + (10!)/((10-10)!10!) (0.4)^10 (0.6)^10\$ |
11 |
Step |
Simplification P(X≥4) |
\$1 - (10!)/(1!9!)(0.4)^9 (0.6)^9 + (10!)/(10!)(0.4)^10 (0.6)^10\$ |
12 |
Step |
After simplification |
1 - [(10×0.0002×0.01) + (1×0.0001×0.0060)] |
13 |
Step |
P(X≤8) |
1 -[0.00002 + 0.0000006] ⇒1-0.0000206 |
14 |
Step |
Probability that in next 10 random orders there will be at most 8 orders in silver P(X≤8) |
0.99 |
15 |
Answer |
D |
|
Tutor: Questions
| Seq | Type | Question | Audio |
|---|---|---|---|
1 |
Problem |
What did you learn from this problem? |
|
2 |
Clue |
What did you learn from the clues? |
|
3 |
Hint |
What did you learn from the Hints? |
|
4 |
Step |
What did you learn from the Steps? |
|
5 |
Step |
How can we improve the Steps? |
Copyright © 2020-2022 saibook.us Contact: info@saibook.us Version: 1.5 Built: 27-February-2023 06:00 AM EST