Lesson Example Discussion Quiz: Class Homework |
Step-2 |
Title: Binomial distribution |
Grade: 9-a Lesson: S4-L4 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
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1 |
Problem |
The random variable X has binomial distribution B(6,0.4). Determine each of the following. |
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2 |
Formula: |
Probability P(x)=\$n_(C_x) p^x q^(n-x)\$ |
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3 |
Step |
From the given data |
n= 20,p=0.4 |
4 |
Step |
Finding the value of q |
q = 1-p q = 1-0.4 ⇒ q=0.6 |
5 |
Step |
P(X≥4) |
P(x=4) + P(x=5) + P(x=6) |
6 |
Step |
Substitute all the values in P(X≥4) |
\$6_(C_4)(0.4)^4(0.6)^(6-4) + 6_(C_5)(0.4)^5(0.6)^(6-5) + 6_(C_6)(0.4)^6(0.6)^(6-6)\$ |
7 |
Hint |
\$n_(C_x) = (n!)/((n-x)!x!)\$ |
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8 |
Step |
P(X≥4) |
\$(6!)/((6-4)!4!) (0.4)^4 (0.6)^4 + (6!)/((6-5)!5!) (0.4)^5 (0.6)^5 +(6!)/((6-6)!6!) (0.4)^6 (0.6)^6\$ |
9 |
Step |
Simplification P(X≥4) |
\$(6!)/(2!4!)(0.4)^4 (0.6)^4 + (6!)/(1!5!)(0.4)^5 (0.6)^5 + (6!)/(0!6!)(0.4)^6 (0.6)^6\$ |
10 |
Step |
After simplification |
(15×0.0256×0.1296) + (6×0.0102×0.0777) + (1×0.0040×0.0466) |
11 |
Step |
P(X≥4) |
0.0497 + 0.0475 + 0.0001 |
12 |
Step |
P(X≥4) |
0.0973 |
13 |
Step |
P(X<2) |
P(x=1) + P(x=0) |
14 |
Step |
Substitute all the values in P(X<2) |
\$6_(C_1)(0.4)^1(0.6)^(6-1) + 6_(C_0)(0.4)^0(0.6)^(6-0)\$ |
15 |
Step |
Simplification P(X<2) |
\$(6!)/((6-1)!1!) (0.4)^1 (0.6)^1 + (6!)/((6-0)!0!) (0.4)^0 (0.6)^0\$ |
16 |
Step |
Simplification |
P(X<2) = \$(6!)/(5!1!)(0.4)^1 (0.6)^1 + (6!)/(6!0!)(0.4)^0 (0.6)^0\$ |
17 |
Step |
After simplification |
(6×0.6×0.4) + (1×1×1) |
18 |
Step |
P(X<2) |
1.44 + 1 |
19 |
Step |
P(X<2) |
2.44 |
20 |
Step |
P(X≥4) = 0.0973 |
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21 |
Answer |
A |
Tutor: Questions
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1 |
Problem |
What did you learn from this problem? |
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2 |
Clue |
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3 |
Hint |
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4 |
Step |
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5 |
Step |
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