Step-2

Title: Binomial distribution

Grade: 9-a Lesson: S4-L4

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

The random variable X has binomial distribution B(6,0.4). Determine each of the following.
a) P(X≥4)
b) P(X<2).?

2

Formula:

Probability P(x)=\$n_(C_x) p^x q^(n-x)\$

3

Step

From the given data

n= 20,p=0.4

4

Step

Finding the value of q

q = 1-p

q = 1-0.4 ⇒ q=0.6

5

Step

P(X≥4)

P(x=4) + P(x=5) + P(x=6)

6

Step

Substitute all the values in P(X≥4)

\$6_(C_4)(0.4)^4(0.6)^(6-4) + 6_(C_5)(0.4)^5(0.6)^(6-5) + 6_(C_6)(0.4)^6(0.6)^(6-6)\$

7

Hint

\$n_(C_x) = (n!)/((n-x)!x!)\$

8

Step

P(X≥4)

\$(6!)/((6-4)!4!) (0.4)^4 (0.6)^4 + (6!)/((6-5)!5!) (0.4)^5 (0.6)^5 +(6!)/((6-6)!6!) (0.4)^6 (0.6)^6\$

9

Step

Simplification P(X≥4)

\$(6!)/(2!4!)(0.4)^4 (0.6)^4 + (6!)/(1!5!)(0.4)^5 (0.6)^5 + (6!)/(0!6!)(0.4)^6 (0.6)^6\$

10

Step

After simplification

(15×0.0256×0.1296) + (6×0.0102×0.0777) + (1×0.0040×0.0466)

11

Step

P(X≥4)

0.0497 + 0.0475 + 0.0001

12

Step

P(X≥4)

0.0973

13

Step

P(X<2)

P(x=1) + P(x=0)

14

Step

Substitute all the values in P(X<2)

\$6_(C_1)(0.4)^1(0.6)^(6-1) + 6_(C_0)(0.4)^0(0.6)^(6-0)\$

15

Step

Simplification P(X<2)

\$(6!)/((6-1)!1!) (0.4)^1 (0.6)^1 + (6!)/((6-0)!0!) (0.4)^0 (0.6)^0\$

16

Step

Simplification

P(X<2) = \$(6!)/(5!1!)(0.4)^1 (0.6)^1 + (6!)/(6!0!)(0.4)^0 (0.6)^0\$

17

Step

After simplification

(6×0.6×0.4) + (1×1×1)

18

Step

P(X<2)

1.44 + 1

19

Step

P(X<2)

2.44

20

Step

P(X≥4) = 0.0973
P(X<2) = 2.44

21

Answer

A

Tutor: Questions

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