Step-1

Title: Inverse Trigonometric Functions

Grade: 1400-a Lesson: S3-L8

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Solve for x: \$2 "tan"^-1("x") = π/3\$.

2

Step

The given equation

\$2 "tan"^-1("x") = π/3\$

3

Step

Divide both sides by 2:

\$(2/2)"tan"^-1("x") = (π/3)/2\$

\$tan^-1("x") = π/6\$

4

Step

Apply the tangent function to both sides to cancel out the inverse tangent:

\$"tan"("tan"^-1("x")) = "tan"(π/6)\$

5

Step

Use the property of inverse and regular tangent functions:

\$("x") = "tan"(π/6)\$

6

Step

Find the value of \$"tan"(π/6)\$:

\$"tan"(π/6) = (\sqrt(3)/3)\$

7

Step

So, the solution for x is \$(\sqrt(3)/3)\$.

8

Choice.A

This is the negative value of the correct solution. In the context of the given equation, it’s not a valid solution

\$-(\sqrt(3)/3)\$

9

Choice.B

This option is the reciprocal of the correct solution. However, the correct solution is \$(\sqrt(3)/3)\$

\$(1/\sqrt(3))\$

10

Choice.C

This is the correct solution obtained by solving the equation \$2 tan^-1(x) = π/3\$

\$(\sqrt(3)/3)\$

11

Choice.D

This is incorrect. It’s the negative of the reciprocal of the correct solution

\$-1/(\sqrt(3))\$

12

Answer

Option

C

13

Sumup

Can you summarize what you’ve understood in the above steps?


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