Step-5

Title: Trigonometry ratios in right triangles

Grade: 1400-a Lesson: S3-L2

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

5

Step Type Explanation Answer

1

Problem

In a triangle XYZ, right-angled at Y, XY = 15 inches, and angle \$ X = 30^o\$. Find cos X.

2

Step

The given values are

XY = 15 inches, \$ X = 30^o\$

3

Step

To find the cosine of angle X in the right triangle XYZ, you can use the definition of cosine, which is the ratio of the adjacent side to the hypotenuse.

4

Step

Find the length of side XZ (the hypotenuse) using trigonometric ratios in a right triangle. Using the sine function, we have:

\$ "cos"("X") = ("Adjacent") / ("Hypotenuse") \$

\$sin(30^o) = "XY"/"XZ"\$

\$1/2 = 15 / "XZ"\$

5

Step

Cross multiply:

\$XZ = 15/(1/2)\$
\$XZ = 15 times 2\$
XZ = 30 inches

6

Step

Now, calculate cosine X:

\$cos(X) = "XY" / "XZ"\$
\$cos(X) = 1/2\$

7

Step

So, the cosine of angle X is \$1/2\$​.

8

Choice.A

Correct representation using the cosine formula

\$1/2\$

9

Choice.B

The cosine function only outputs values between -1 and 1. Therefore, -2 is not a possible value for the cosine function so wrong

-2

10

Choice.C

This is incorrect. It states \$−1/2\$​, which is the cosine of 60 degrees, not 30 degrees

\$-1/2\$

11

Choice.D

The cosine of an angle cannot be greater than 1 or less than -1 because the cosine function’s range is between -1 and 1 so wrong

2

12

Answer

Option

A

13

Sumup

Can you briefly tell me what you’ve learned and understood in today’s lesson?


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