Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Trigonometry function( sine, cosine, tangent) |
Grade: 1400-a Lesson: S3-L1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Evaluate the following expression: \$ sin(pi/3) cos(pi/6) + cos(pi/3) sin(pi/6) \$. |
|
2 |
Step |
Let’s evaluate the given expression step by step: |
\$ sin(pi/3) cos(pi/6) + cos(pi/3) sin(pi/6) \$ |
3 |
Hint |
First, let’s use the trigonometric identities: |
\$ sin(pi/3) = \sqrt3 / 2 \$ \$ cos(pi/3) = 1/2 \$ \$ sin(pi/6) = 1/2 \$ \$ cos(pi/6) = \sqrt3 / 2 \$ |
4 |
Step |
Now substitute these values into the expression: |
\$ \sqrt3 / 2 times \sqrt3 / 2 + 1/2 times 1/2 \$ |
5 |
Step |
Simplify further: |
\$ 3/4 + 1/4 \$ |
6 |
Step |
Combine the terms: |
\$ 4/4 = 1 \$ |
7 |
Step |
So, the evaluated value of the expression is 1. |
|
8 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
|
9 |
Choice.A |
This is correct because after the evaluation the result is 1 |
1 |
10 |
Choice.B |
This is incorrect because after the evaluation the result is not 1 |
\$ 1/2\$ |
11 |
Choice.C |
This is incorrect because after the evaluation the result is not 1 |
\$ \sqrt3/2\$ |
12 |
Choice.D |
This is incorrect because after the evaluation the result is not 1 |
\$ \sqrt 3\$ |
13 |
Answer |
Option |
A |
14 |
Sumup |
Can you briefly tell me what you’ve learned and understood in today’s lesson? |
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