Step-2

Title: System of Linear Equations with Infinite Solutions

Grade: 1400-a Lesson: S1-L7

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

In the system of equations above, h and p are constants. If the system has infinitely many solutions, what is the value of h - p: - x + 6y = 9 and hy - px = 81

2

Step

The given system of equation are

-x + 6y = 9 equation(1)

hy - px = 81 equation(2)

3

Step

Equation(1) is multiply by the number is 9

9(-x + 6 y = 9)

-9x + 54 y = 81 equation(3)

4

Step

Since both equations (2) and (3) are now equal to 81. So , now set them equal to each other

5

Step

Then find values of h and p

hy - px = -9x + 54y

hy - px = 54y - 9x

So, here h = 54 and p = 9

6

Step

Then now find the value if h - p

h - p = 54 - 9
h - p = 45

7

Step

So therefore the value of h - p = 45.

8

Choice.A

TThis is wrong due to miscalculations

50

9

Choice.B

This is correct due to accurately done the calculations

45

10

Choice.C

This is wrong due to miscalculations

40

11

Choice.D

This is wrong due to miscalculations

54

12

Answer

Option

B

13

Sumup

Can you summarize what you’ve understood in the above steps?


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