Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Trigonometry equations |
Grade: 1300-a Lesson: S3-L5 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Solve the equation: \$sin(2x) = 1/2\$ on (0,2π). |
|
2 |
Step |
The given equation is |
\$sin(2x) = 1/2\$ on (0,2π) |
3 |
Hint |
If \$sin(θ) = 1/2\$, we know θ is in quadrants II and III. While \$θ = sin−1(1/2)\$. Therefore, the possible angles are \$θ = (pi)/6 and (5pi)/6\$. |
|
4 |
Step |
In quadrant II \$2x = (pi)/6\$ |
\$2x = (pi)/6 + (2pi)\$ |
5 |
Step |
After simplifying the equation |
\$2x = ((pi) + (12pi)) / 6\$ \$x = (13pi)/(12)\$ |
6 |
Step |
In quadrant IIi \$2x = (5pi)/6\$ |
\$2x =(5pi)/6 + (2pi)\$ |
7 |
Step |
After performing simplification |
\$2x = ((5pi) + (12pi)) /6\$ \$x = (17pi) / (12)\$ |
8 |
Step |
So, the solutions for θ are \$(13pi)/12 and (17pi)/12 \$. |
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9 |
Choice.A |
This choice is incorrect. The provided solutions do not lie within the specified interval |
\$(13pi)/12, (12pi)/13\$ |
10 |
Choice.B |
This solution is accurate because the calculations were done correctly |
\$(13pi)/12, (17pi)/12\$ |
11 |
Choice.C |
This choice is incorrect, as \$(12pi)/17\$ is outside the given interval |
\$(13pi)/12, (12pi)/17\$ |
12 |
Choice.D |
This option is incorrect. The \$(12pi)/13\$ is not a solution within the specified interval, and \$(17pi)/12\$ is correct |
\$(12pi)/13, (17pi)/12\$ |
13 |
Answer |
Option |
B |
14 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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