Solve the quadratic equation: \$2x^2 + 5x - 3 = 0\$.

The quadratic formulae

\$ x = (-b ± \sqrt(b^2 - 4ac)) / (2a) \$

Substitute the corresponding values using the quadratic formulae

a = 2, b = 5, and c = - 3

\$x = (-5 ± \sqrt (5^2 - 4 times 2 times (-3))) / (2 times 2)\$

\$ x = (-5 ± 7) / 4 \$

The two possible solutions are

\$(-5 + 7) / 4\$ and \$(-5 - 7) / 4\$

Following the cancellation of the equation

\$x = \cancel2^1 / \cancel4^2\$ and \$x = \cancel(-12)^3 / \cancel4^1\$

⇒ \$x = 1/2 \$ and x = - 3

Therefore, the solutions to the equation stem:\$2x^2 + 5x - 3 = 0\$ are

\$x = 1/2 and x = -3\$

Both solutions to the quadratic equation are accurate and acceptable

\$x = 1/2 \$ and x = - 3

The solutions for the quadratic equations are not precise

\$x = 3/2 \$ and x = - 4

The solutions for the quadratic equations are not precise

\$x = 2/3 \$ and x = 3

The solutions for the quadratic equations are not precise

x = - 0.6 and x = 4

Option

A

Can you summarize what you’ve understood in the above steps?