Step-5

Title: Law of sines and cosines

Grade: 10-a Lesson: S3-L7

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Solve triangle ABC, given a = 15, b = 25, and c = 28. Find the angle A , B and C?

2

Step

The given value are

a = 15, b = 25, and c = 28

3

Formula:

The Law of Cosines states for CosA:

\$CosA = ((b)^2 + (c)^2 - (a)^2)/(2bc)\$

4

Step

Plug the values in the formula and then simplify for the value of CosA

\$CosA = ((25)^2 + (28)^2 - (15)^2) / (2 times 25 times 28)\$

\$CosA = (625 + 784 - 225) / (1(400))\$

\$CosA = 0.845\$

\$A = cos^-1 (0.845)\$

A = 32.3°

5

Formula:

The Law of Cosines states for CosB:

\$CosB = ((a)^2 + (c)^2 - (b)^2) / (2ac)\$

6

Step

Plug the values in the formula and then simplify for the value of CosB

\$CosB = ((15)^2 + (28)^2 - (25)^2) / (2 times 15 times 28)\$

\$CosB = (225 + 784 - 625) / (840)\$

\$CosB = 0.457\$

\$B = cos^-1(0.457)\$

B = 62.8°

7

Step

The sum angle in a triangle is 180°, so now find the value CosC

C = 180 - (A + B)

C = 180 - ( 32.3 + 62.8)

C = 84.9°

8

Step

So, the angles of triangle ABC are A = 32.3°, B = 62.8° and C = 84.9°.

9

Choice.A

Incorrect because the values for angles A and B are slightly off

A = 32°, B = 63° and C = 84.9°

10

Choice.B

Correct: It is accurately done the calculation by using the law of cosines formula

A = 32.3°, B = 62.8° and C = 84.9°

11

Choice.C

Wrong regarding angle C and B . The correct value should be approximately 84.7°, not 85° and angle B is 62.8 degree not 63 degrees

A = 32.3°, B = 63° and C = 85°

12

Choice.D

Option D is inaccurate as the calculated angle A and values for B and C differ from the provided data

A = 32.8°, B = 62.3° and C = 83.9°

13

Answer

Option

B

14

Sumup

Can you summarize what you’ve understood in the above steps?


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