Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Law of sines and cosines |
Grade: 10-a Lesson: S3-L7 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Solve triangle ABC, given a = 15, b = 25, and c = 28. Find the angle A , B and C? |
|
2 |
Step |
The given value are |
a = 15, b = 25, and c = 28 |
3 |
Formula: |
The Law of Cosines states for CosA: |
\$CosA = ((b)^2 + (c)^2 - (a)^2)/(2bc)\$ |
4 |
Step |
Plug the values in the formula and then simplify for the value of CosA |
\$CosA = ((25)^2 + (28)^2 - (15)^2) / (2 times 25 times 28)\$ \$CosA = (625 + 784 - 225) / (1(400))\$ \$CosA = 0.845\$ \$A = cos^-1 (0.845)\$ A = 32.3° |
5 |
Formula: |
The Law of Cosines states for CosB: |
\$CosB = ((a)^2 + (c)^2 - (b)^2) / (2ac)\$ |
6 |
Step |
Plug the values in the formula and then simplify for the value of CosB |
\$CosB = ((15)^2 + (28)^2 - (25)^2) / (2 times 15 times 28)\$ \$CosB = (225 + 784 - 625) / (840)\$ \$CosB = 0.457\$ \$B = cos^-1(0.457)\$ B = 62.8° |
7 |
Step |
The sum angle in a triangle is 180°, so now find the value CosC |
C = 180 - (A + B) C = 180 - ( 32.3 + 62.8) C = 84.9° |
8 |
Step |
So, the angles of triangle ABC are A = 32.3°, B = 62.8° and C = 84.9°. |
|
9 |
Choice.A |
Incorrect because the values for angles A and B are slightly off |
A = 32°, B = 63° and C = 84.9° |
10 |
Choice.B |
Correct: It is accurately done the calculation by using the law of cosines formula |
A = 32.3°, B = 62.8° and C = 84.9° |
11 |
Choice.C |
Wrong regarding angle C and B . The correct value should be approximately 84.7°, not 85° and angle B is 62.8 degree not 63 degrees |
A = 32.3°, B = 63° and C = 85° |
12 |
Choice.D |
Option D is inaccurate as the calculated angle A and values for B and C differ from the provided data |
A = 32.8°, B = 62.3° and C = 83.9° |
13 |
Answer |
Option |
B |
14 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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