Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Area of Triangle |
Grade: 8-a Lesson: S3-L2 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Find the area of the equilateral triangle ABC, where AB = AC = BC = 8cm. |
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2 |
Step |
Given that AB = 8cm , BC = 8cm ,CA = 8cm |
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3 |
Formula: |
To find the area of an equilateral triangle, you can use the formula |
A = \$(sqrt 3)/4 \times (a)^2\$ ( hint a = sides ) |
4 |
Step |
Substitute the values into the formula |
A = \$((sqrt3) / 4 \times (8 cm)^2 )\$ |
5 |
Step |
Calculate the area |
A = \$(sqrt3) / 4 \times 64 (cm)^2\$ A = \$((sqrt3) \times64)/4 (cm)^2\$ |
6 |
Step |
After Simplify the equation |
A = \$(sqrt3) \times 16(cm)^2\$ A = \$16(sqrt3)(cm)^2\$ |
7 |
Step |
Therefore, the area of the equilateral triangle ABC is \$16(sqrt3)(cm)^2\$ |
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8 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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9 |
Choice.A |
Incorrect, as the correct area is \$16(sqrt3)(cm)^2\$ |
\$14(sqrt3)(cm)^2\$ |
10 |
Choice.B |
Correctly calculating an equilateral triangle’s area (side length 8 cm) affirms its accuracy with precision |
\$16(sqrt3)(cm)^2\$ |
11 |
Choice.C |
Incorrect, as the correct area is \$16(sqrt3)(cm)^2\$ |
\$13(sqrt3)(cm)^2\$ |
12 |
Choice.D |
Incorrect. The area should have units of square centimeters \$cm^2\$, not centimeters cm |
\$15(sqrt3)(cm)^2\$ |
13 |
Answer |
Option |
B |
14 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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