Lesson Example Discussion Quiz: Class Homework |
Step-2 |
Title: Perimeter of Traiangle |
Grade: 1400-a Lesson: S3-L3 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
If two sides of a triangle are 9 cm and 6 cm and its perimeter is 26 cm.Find the third side of the triangle. |
|
2 |
Step |
Given, Perimeter(P) is side 1(a) is side 2(b) is |
\$26\$cm \$9\$cm \$6\$cm |
3 |
Formula: |
Perimeter of Triangle (P) |
P = a + b + c |
4 |
Step |
Substitute the values into the formula: |
26 = 9 + 6 + c |
5 |
Step |
Here,we are finding the "c" value |
c = 26 - 15 c = 11 cm |
6 |
Step |
Therefore, the third side(c) of a triangle is 11 cm. |
|
7 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
8 |
Choice.A |
13 is greater than the sum of the given sides(9 + 6).so it’s not a valid option |
13 cm |
9 |
Choice.B |
It is correct answer, because it satisfies the conditions for a valid triangle |
11 cm |
10 |
Choice.C |
Incorrect. 12 is not a valid option for a triangle because it results in a degenerate triangle where all sides lie along the same line |
12 cm |
11 |
Choice.D |
Incorrect. It is greater than the sum of the given sides(9 + 6), so it’s not a valid option |
14 cm |
12 |
Answer |
Option |
B |
13 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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