Step-1

Title: Find the length and perimeter

Grade: 6-a Lesson: S2-L4

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

The perimeter of a rectangle is 267 ft. The width of the rectangle is 1/7th of the perimeter. What is the length of the rectangle?

2

Step

The given values are

perimeter 267 ft and the width of the rectangle is \$1/7\$th od the perimeter

3

Formula:

The perimeter of rectangle is

P = 2[length + width]

4

Hint

Here, the width of the rectangle is \$1/7\$th od the perimeter

\$(1/7) times P\$

5

Step

Now substitute the perimeter value

\$1/7 times 267\$

6

Step

After simplification

B = 38.14 ft

7

Step

Now substitute the values in the perimeter formula

267 = 2[l + 38.14]

8

Step

After simplification

133.5 = l + 38.14

9

Step

After simplification

l = 133.5 - 38.14

10

Step

After simplification

l = 95.36 ft

11

Step

The length of the rectangle is l = 95.36 ft

12

Sumup

Can you summarize what you’ve understood in the above steps?

13

Choice.A

This is wrong because it does not match the calculated value of the length of the rectangle

96.35 ft

14

Choice.B

This is correct because it match the calculated value of the length of the rectangle

95.36 ft

15

Choice.C

This is wrong because it does not match the calculated value of the length of the rectangle

96.53 ft

16

Choice.D

This is wrong because it does not match the calculated value of the length of the rectangle

95.63 ft

17

Answer

Option

B

18

Sumup

Can you summarize what you’ve understood in the above steps?


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