If the radius of a sector is 14cm and \$\theta = 90^0\$. Find the arc length?

Arc length of a sector.

l = \$\frac{\theta}{360^\circ} \times 2 \times \pi r\$

Substitute \$22/7\$ for \$pi\$, \$90^\circ\$ for \$\theta\$ and 14 for r

l = \$\frac{90°}{360°} \times 2 \times \frac{22}{7} \times 14\$

Cancel out common factor.

\$ l = \frac{\cancel{90°} ^{1}}{\cancel{360°} ^{4}} \times 2 \times \frac{22}{\cancel{7}^1} \times \cancel{14}^2 \$

Cancel out common factor.

\$l = \frac{1}{\cancel{4}^2} \times \cancel{2}^1 \times \frac{22}{1} \times 2\$

Cancel out common factor.

\$l = \frac{1}{\cancel{2}^1} \times 1 \times\frac{\cancel{22} ^{11}}{1} \times 2 \$ \end{align}

Multiply.

\$l = 22 \$

Answer

The arc length is \$22 cm\$