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Step-5

Title: Miscellaneous - 2

Grade: 7-a Lesson: S1-L10

Explanation:

Step	Type	Explanation	Answer
1	Problem	An ox in an oil processing appratus is thered to a rope 3m long. How much distance does it cover in 14 rounds?
2	Given	Given An ox in an oil processing apparatus is tethered to a rope 3 m long.
3	Step	Radius of the circular path traced by the ox is	3 m
4	Step	And distance covered by an ox in 1 round= Circumference of the circular path.
5	Formula:	Circumference of the circular path.	C= 2 π r
6	Step	Substitute \$22/7\$ for\$\pi\$ and 3 m for r.	\$C = 2 \times \frac{22}{7} \times 3 m.\$
7	Step	Multiply.	\$C = \frac{132}{7} m. \$
8	Step	Distance covered in 14 rounds is	\$\frac{132}{7} \times 14 m\$
9	Step	Cancel out the common factor.	\$\frac{132}{\cancel{7}^1} \times \cancel{14}^2 m\$
10	Step	Multiply.	264 m
11		Answer	Distance covered in 14 rounds is 264 m.

Step

Type

Explanation

Answer

Problem

An ox in an oil processing appratus is thered to a rope 3m long. How much distance does it cover in 14 rounds?

Given

Given An ox in an oil processing apparatus is tethered to a rope 3 m long.

Step

Radius of the circular path traced by the ox is

3 m

Step

And distance covered by an ox in 1 round= Circumference of the circular path.

Formula:

Circumference of the circular path.

C= 2 π r

Step

Substitute \$22/7\$ for\$\pi\$ and 3 m for r.

\$C = 2 \times \frac{22}{7} \times 3 m.\$

Step

Multiply.

\$C = \frac{132}{7} m. \$

Step

Distance covered in 14 rounds is

\$\frac{132}{7} \times 14 m\$

Step

Cancel out the common factor.

\$\frac{132}{\cancel{7}^1} \times \cancel{14}^2 m\$

Step

Multiply.

264 m

Answer

Distance covered in 14 rounds is 264 m.