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Lesson Example Discussion Quiz: Class Homework

Step-5

Title: Construction of Triangles (Based on angles)

Grade: 10-a Lesson: S3-L2

Explanation:

Lesson Steps

Step	Type	Explanation	Answer
1	Problem	$5$ Construct a \$triangleMNP\$ with the base NP = 10.8 units , \$angleN = 25°\$ and \$angle P = 38°\$.
2	Clue	Given \$triangleMNP\$ with the base NP = 10.8 units and \$angleN = 25°\$, and \$angleP = 38°\$
3	Step	Use a ruler and draw a horizontal line of length 10.8 units. Name the end points of this line as NP.
4	Step	Place the center of the protactor on N and look for 25° in the scale of the protactor and mark it as point M.
5	Step	Now, place the centre of the protactor on U ad look for 38° in the protactor.
6	Step	join NP and PM
7	Step	It should be note that the third angle , which is \$angleP\$ can be found using the angle sum property of triangle ,so \$angleP = 180 -(25+38) = 117°\$.

Step

Type

Explanation

Answer

Problem

$5$

Construct a \$triangleMNP\$ with the base NP = 10.8 units , \$angleN = 25°\$ and \$angle P = 38°\$.

Clue

Given \$triangleMNP\$ with the base NP = 10.8 units and \$angleN = 25°\$, and \$angleP = 38°\$

Step

Use a ruler and draw a horizontal line of length 10.8 units. Name the end points of this line as NP.

Step

Place the center of the protactor on N and look for 25° in the scale of the protactor and mark it as point M.

Step

Now, place the centre of the protactor on U ad look for 38° in the protactor.

Step

join NP and PM

Step

It should be note that the third angle , which is \$angleP\$ can be found using the angle sum property of triangle ,so \$angleP = 180 -(25+38) = 117°\$.