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Lesson Example Discussion Quiz: Class Homework

Step-3

Title: Construction of Triangles (Based on angles)

Grade: 10-a Lesson: S3-L2

Explanation:

Lesson Steps

Step	Type	Explanation	Answer
1	Problem	$3$ Construct a right \$trianglePQR\$ in which \$angle Q = 90°\$ and \$angle R = 45°\$, QR = 6.3 cm.
2	Clue	Given\$trianglePQR\$ with the base 6.3 cm and \$angleQ = 90°\$, and \$angleR = 45°\$
3	Step	Use a ruler and draw a horizontal line of length 6.3 cm. Name the end points of this line as QR.
4	Step	Place the center of the protactor on Q and look for 90° in the scale of the protactor and mark it as point P.
5	Step	Now, place the centre of the protactor on R ad look for 45° in the protactor.
6	Step	join PQ and PR
7	Step	It should be note that the third angle , which is \$angleP\$ can be found using the angle sum property of triangle ,so \$angleP = 180 -(90+45) = 45°\$.

Step

Type

Explanation

Answer

Problem

$3$

Construct a right \$trianglePQR\$ in which \$angle Q = 90°\$ and \$angle R = 45°\$, QR = 6.3 cm.

Clue

Given\$trianglePQR\$ with the base 6.3 cm and \$angleQ = 90°\$, and \$angleR = 45°\$

Step

Use a ruler and draw a horizontal line of length 6.3 cm. Name the end points of this line as QR.

Step

Place the center of the protactor on Q and look for 90° in the scale of the protactor and mark it as point P.

Step

Now, place the centre of the protactor on R ad look for 45° in the protactor.

Step

join PQ and PR

Step

It should be note that the third angle , which is \$angleP\$ can be found using the angle sum property of triangle ,so \$angleP = 180 -(90+45) = 45°\$.