Lesson Example Discussion Quiz: Class Homework |
Step-1 |
Title: |
Grade: 10-a Lesson: S2-L7 |
Explanation: |
Description: 1
Steps | Statement | Solution |
---|---|---|
1 |
\begin{align} \text{Given} \\ \end{align} |
\begin{align} \text{ABCD is a parallelogram, AB = 11b, DC = 1331 and BC = 2b.} \\ \end{align} |
2 |
Consider \$\triangle ABC\$ and \$\triangle CDA\$ |
\begin{align} AC &= CA \\ AB &= CD \\ BC &= DA \\ \triangle ABC &\cong \triangle CDA \\ \end{align} |
3 |
From \$\triangle ABC\$ and \$\triangle CDA\$ |
\begin{align} && AB &= CD \\ \Rightarrow && 11b &= 1331 \\ \Rightarrow && b &= 121\\ \end{align} |
4 |
\begin{align} \text{Calculating the lenght of BC} \\ \end{align} |
\begin{align} && BC &= 2b \\ \Rightarrow && BC &= 2(121) \\ \Rightarrow && BC &= 242 \\ \end{align} |
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